'''
	problem--
	Given a time in 12-hour AM/PM format, convert it to military (24-hour) time.
	Note: Midnight is 12:00:00AM on a 12-hour clock, and 00:00:00 on a 24-hour clock. Noon is 12:00:00PM on a 12-hour clock, and 12:00:00 on a 24-hour clock.
	Function Description--
	Complete the timeConversion function in the editor below. It should return a new string representing the input time in 24 hour format.
	timeConversion has the following parameter(s):
	s: a string representing time in 12 hour format
	Input Format--
	A single string containing a time in 12-hour clock format (i.e.:hh:mm:ssAM or hh:mm:ssPM) ,where 00<=hh<=12 and 00<=mm,ss<=59.
	Constraints--
	All input times are valid
	Output Format--
	Convert and print the given time in 24-hour format, where 00<=hh<=23.
	Sample Input 0--
	07:05:45PM
	Sample Output 0--
	19:05:45
	'''
	# Here is my solution to the question given in HackerRank site s=input() time="" if (s[8:10]=='AM' and int(s[0:2]+s[3:5]+s[6:8])<=116059):     time=s[0:8]     print(time) elif (s[8:10]=='AM' and int(s[0:2]+s[3:5]+s[6:8])>=120000 and int(s[0:2]+s[3:5]+s[6:8])<=126059):     #time=str(int(s[0:2])-12)+'0'+s[2:8]       time=str(int(s[0:2])-12)+'0'+s[2:8]     print(time) elif (s[8:10]=='PM' and int(s[0:2]+s[3:5]+s[6:8])>=120000 and int(s[0:2]+s[3:5]+s[6:8])<=126059):     time=s[0:8]     print(time) else:     time=str((int(s[0:2]))+12)+s[2:8]     print(time)