| ''' | |
| problem-- | |
| Given a time in 12-hour AM/PM format, convert it to military (24-hour) time. | |
| Note: Midnight is 12:00:00AM on a 12-hour clock, and 00:00:00 on a 24-hour clock. Noon is 12:00:00PM on a 12-hour clock, and 12:00:00 on a 24-hour clock. | |
| Function Description-- | |
| Complete the timeConversion function in the editor below. It should return a new string representing the input time in 24 hour format. | |
| timeConversion has the following parameter(s): | |
| s: a string representing time in 12 hour format | |
| Input Format-- | |
| A single string containing a time in 12-hour clock format (i.e.:hh:mm:ssAM or hh:mm:ssPM) ,where 00<=hh<=12 and 00<=mm,ss<=59. | |
| Constraints-- | |
| All input times are valid | |
| Output Format-- | |
| Convert and print the given time in 24-hour format, where 00<=hh<=23. | |
| Sample Input 0-- | |
| 07:05:45PM | |
| Sample Output 0-- | |
| 19:05:45 | |
| ''' | |
| # Here is my solution to the question given in HackerRank site
s=input() time="" if (s[8:10]=='AM' and int(s[0:2]+s[3:5]+s[6:8])<=116059): time=s[0:8] print(time) elif (s[8:10]=='AM' and int(s[0:2]+s[3:5]+s[6:8])>=120000 and int(s[0:2]+s[3:5]+s[6:8])<=126059): #time=str(int(s[0:2])-12)+'0'+s[2:8] time=str(int(s[0:2])-12)+'0'+s[2:8] print(time) elif (s[8:10]=='PM' and int(s[0:2]+s[3:5]+s[6:8])>=120000 and int(s[0:2]+s[3:5]+s[6:8])<=126059): time=s[0:8] print(time) else: time=str((int(s[0:2]))+12)+s[2:8] print(time) | |
